Codeforces 785A - Anton and Polyhedrons
Anton’s favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
● Tetrahedron. Tetrahedron has 4 triangular faces.
● Cube. Cube has 6 square faces.
● Octahedron. Octahedron has 8 triangular faces.
● Dodecahedron. Dodecahedron has 12 pentagonal faces.
● Icosahedron. Icosahedron has 20 triangular faces.
All five kinds of polyhedrons are shown on the picture below:
Anton has a collection of n polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!
Input:
The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of polyhedrons in Anton’s collection.
Each of the following n lines of the input contains a string si — the name of the i-th polyhedron in Anton’s collection.
The string can look like this:
● “Tetrahedron” (without quotes), if the i-th polyhedron in Anton’s collection is a tetrahedron.
● “Cube” (without quotes), if the i-th polyhedron in Anton’s collection is a cube.
● “Octahedron” (without quotes), if the i-th polyhedron in Anton’s collection is an octahedron.
● “Dodecahedron” (without quotes), if the i-th polyhedron in Anton’s collection is a dodecahedron.
● “Icosahedron” (without quotes), if the i-th polyhedron in Anton’s collection is an icosahedron.
Output:
Output one number — the total number of faces in all the polyhedrons in Anton’s collection.
範例:
input:
1 | 4 |
output:
1 | 42 |
input:
1 | 3 |
output:
1 | 28 |
Note:
In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces.
題意:
計算輸入的多面體總共面數是多少？
思路:
根據輸入的字串累加對應的面即可。